(x-3)^2-5=-8x+7

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Solution for (x-3)^2-5=-8x+7 equation: 



(x-3)^2-5=-8x+7

We move all terms to the left:

(x-3)^2-5-(-8x+7)=0

We get rid of parentheses

(x-3)^2+8x-7-5=0

We add all the numbers together, and all the variables

8x+(x-3)^2-12=0

We move all terms containing x to the left, all other terms to the right

8x+(x-3)^2=12

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